ysako’s note
2024-04-01
How-to
test
test1
見出し1
test2
見出し2
test3
見出し3
画像
数式
f
(
x
∣
μ
,
σ
2
)
=
1
2
π
σ
2
exp
(
−
(
x
−
μ
)
2
2
σ
2
)
f(x | \mu, \sigma^2) = \frac{1}{\sqrt{2\pi\sigma^2}} \exp\left(-\frac{(x - \mu)^2}{2\sigma^2}\right)
f
(
x
∣
μ
,
σ
2
)
=
2
π
σ
2
1
exp
(
−
2
σ
2
(
x
−
μ
)
2
)
where:
μ
\mu\
μ
is the mean of the distribution,
σ
2
\sigma^2 \
σ
2
is the variance of the distribution,
σ
\sigma \
σ
is the standard deviation of the distribution.
How-to
test